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db-lesson/【練習問題】 SQL/Question2/Questions2_中野.txt
2026-09-28 14:38:10 +09:00

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問1
CREATE TABLE item_category(category_id INT AUTO_INCREMENT, category_name VARCHAR(256) NOT NULL, PRIMARY KEY (category_id));
INSERT INTO item_category (category_name) VALUES ('家具');
INSERT INTO item_category (category_name) VALUES ('飲料');
INSERT INTO item_category (category_name) VALUES ('食品');
問2
CREATE TABLE items(item_id INT AUTO_INCREMENT, name VARCHAR(256) NOT NULL, price INT NOT NULL, category_id INT, PRIMARY KEY (item_id));
ALTER TABLE items ADD FOREIGN KEY(category_id) REFERENCES item_category(category_id);
INSERT INTO items(name, price, category_id) VALUES('ローマのテーブル', 150000, 1);
INSERT INTO items(name, price, category_id) VALUES('げーたるーど2000 500ml', 370, 2);
INSERT INTO items(name, price, category_id) VALUES('原子肉', 2500, 3);
INSERT INTO items(name, price, category_id) VALUES('魅惑の椅子', 100000, 1);
問3
SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id;
問4
SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id ORDER BY items.price ASC;
問5
SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE item_category.category_name = '家具';
問6
SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE price >= 1000 AND price <= 50000;
問7
SELECT COUNT(*) AS data_count FROM items;
問8
SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE price = (SELECT MAX(price) FROM items);
問9
SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE name LIKE '%の%';