q２_更新

【練習問題】 SQL/Question1/Question1.txt

@@ -1,23 +0,0 @@
-問１
-テーブル作成
- CREATE TABLE book_table (book_id INT, book_name VARCHAR(50), author_name VARCHAR(50), price INT, sales_flag INT);
-問２
- INSERT INTO book_table VALUES (10001, 'TwoPeace', '三田英一郎', 420,1);
-INSERT INTO book_table VALUES (10002, '名探偵金田二', '青山ふみや', 460,1);
-INSERT INTO book_table VALUES (20001, '坊ちゃま', '冬目漱岩', 460,1);
-INSERT INTO book_table VALUES (30001, '西方見聞録', '不明', 1000,1);
-INSERT INTO book_table VALUES (40010, '吾輩は犬である', '冬目漱岩', 420,1);
-
-問３
-SELECT book_name , author_name FROM book_table;
-
-問４
- UPDATE book_table SET sales_flag= 0 WHERE book_id =30001;
-
-問５
-SELECT * FROM book_table WHERE sales_flag LIKE '%1%';
-
-問６
-SELECT * FROM book_table WHERE author_name = '冬目漱岩' AND price = 420;
-問７
- DELETE FROM book_table WHERE book_id = 20001;

【練習問題】 SQL/Question1/q1.txt

@@ -0,0 +1,28 @@
+問1
+CREATE TABLE book_table (book_id INT,book_name VARCHAR(50),author_name VARCHAR(50),price INT,sales_flag INT );
+
+問2
+INSERT INTO book_table VALUES(10001, 'TwoPeace','三田英一郎',420,1);
+INSERT INTO book_table VALUES(10002, '名探偵金田二','青山ふみや',460,1);
+INSERT INTO book_table VALUES(20001, '坊ちゃま','冬目漱岩',460,1);
+INSERT INTO book_table VALUES(30001, '西方見聞録','不明',1000,1);
+INSERT INTO book_table VALUES(40010, '吾輩は犬である','冬目漱岩',420,1);
+
+SELECT * FROM book_table;
+
+問3
+SELECT book_name,author_name FROM book_table;
+
+問4
+UPDATE book_table SET sales_flag =  0 WHERE book_id = 30001;
+
+問5
+SELECT book_id, book_name, author_name,price, sales_flag FROM book_table where sales_flag = 1;
+
+問6
+SELECT book_id, book_name, author_name,price, sales_flag FROM book_table where author_name = '冬目漱岩' AND price = 420;
+
+問7
+DELETE FROM book_table WHERE book_id = 20001;
+SELECT * FROM book_table;
+

【練習問題】 SQL/Question2/Question2.txt

@@ -1,132 +0,0 @@
-問題1
-mysql> CREATE TABLE item_category (
-    ->     category_id INT AUTO_INCREMENT PRIMARY KEY,
-    ->     category_name VARCHAR(256) NOT NULL
-    -> );
-Query OK, 0 rows affected (0.03 sec)
-
-mysql> INSERT INTO item_category ('家具');
-ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''家具')' at line 1
-mysql> ^C
-mysql>
-mysql> INSERT INTO item_category (category_name) VALUES ('家具');
-Query OK, 1 row affected (0.01 sec)
-
-mysql> INSERT INTO item_category (category_name) VALUES ('飲料');
-Query OK, 1 row affected (0.00 sec)
-
-mysql> INSERT INTO item_category (category_name) VALUES ('食品');
-Query OK, 1 row affected (0.00 sec)
-
-mysql> SELECT * FROM item_category;
-+-------------+---------------+
-| category_id | category_name |
-+-------------+---------------+
-|           1 | 家具          |
-|           2 | 飲料          |
-|           3 | 食品          |
-+-------------+---------------+
-3 rows in set (0.00 sec)
-
-問題２
-CREATE TABLE items ( item_id INT AUTO_INCREMENT PRIMARY KEY, name VARCHAR(256), price INT, category_id INT, FOREIGN KEY (category_id) REFERENCES item_category(category_id));
-
-INSERT INTO items (name, price, category_id)
-    -> VALUES ('ローマのテーブル', 150000, 1);
-INSERT INTO items (name, price, category_id) VALUES ('げーたるど2000 500 ml', 370, 2);
-mysql> INSERT INTO items (name, price, category_id) VALUES ('原始肉', 2500, 3);
-Query OK, 1 row affected (0.00 sec)
-
-mysql> INSERT INTO items (name, price, category_id) VALUES ('魅惑の橋子', 100000, 1);
-Query OK, 1 row affected (0.00 sec)
-問題３
-SELECT * FROM items JOIN item_category USING (category_id);
-+-------------+---------+-----------------------+--------+---------------+
-| category_id | item_id | name                  | price  | category_name |
-+-------------+---------+-----------------------+--------+---------------+
-|           1 |       1 | ローマのテーブル      | 150000 | 家具          |
-|           1 |       4 | 魅惑の橋子            | 100000 | 家具          |
-|           2 |       2 | げーたるど2000 500 ml |    370 | 飲料          |
-|           3 |       3 | 原始肉                |   2500 | 食品          |
-+-------------+---------+-----------------------+--------+---------------+
-4 rows in set (0.00 sec)
-
-問題４
-SELECT * 
-FROM items 
-JOIN item_category USING (category_id)
-ORDER BY price ASC;
-+-------------+---------+-----------------------+--------+---------------+
-| category_id | item_id | name                  | price  | category_name |
-+-------------+---------+-----------------------+--------+---------------+
-|           2 |       2 | げーたるど2000 500 ml |    370 | 飲料          |
-|           3 |       3 | 原始肉                |   2500 | 食品          |
-|           1 |       4 | 魅惑の橋子            | 100000 | 家具          |
-|           1 |       1 | ローマのテーブル      | 150000 | 家具          |
-+-------------+---------+-----------------------+--------+---------------+
-4 rows in set (0.00 sec)
-
-問題５
- SELECT * FROM items JOIN item_category USING (category_id) WHERE category_name = '家具';
-+-------------+---------+------------------+--------+---------------+
-| category_id | item_id | name             | price  | category_name |
-+-------------+---------+------------------+--------+---------------+
-|           1 |       1 | ローマのテーブル | 150000 | 家具          |
-|           1 |       4 | 魅惑の橋子       | 100000 | 家具          |
-+-------------+---------+------------------+--------+---------------+
-2 rows in set (0.00 sec)
-
-問題　６
-mysql> SELECT * FROM items JOIN item_category USING (category_id) WHERE price BETWEEN 1000 AND 50000;
-+-------------+---------+--------+-------+---------------+
-| category_id | item_id | name   | price | category_name |
-+-------------+---------+--------+-------+---------------+
-|           3 |       3 | 原始肉 |  2500 | 食品          |
-+-------------+---------+--------+-------+---------------+
-1 row in set (0.00 sec)
-
-問題７
-mysql> SELECT COUNT(*) AS total_items FROM items;
-+-------------+
-| total_items |
-+-------------+
-|           4 |
-+-------------+
-1 row in set (0.00 sec)
-
-問題８
-mysql> SELECT * FROM items WHERE price = (SELECT MAX(price) FROM items);
-+---------+------------------+--------+-------------+
-| item_id | name             | price  | category_id |
-+---------+------------------+--------+-------------+
-|       1 | ローマのテーブル | 150000 |           1 |
-+---------+------------------+--------+-------------+
-1 row in set (0.00 sec)
-
-問題９
-
-
-mysql> SELECT * FROM items WHERE name LIKE '%の%';
-+---------+------------------+--------+-------------+
-| item_id | name             | price  | category_id |
-+---------+------------------+--------+-------------+
-|       1 | ローマのテーブル | 150000 |           1 |
-|       4 | 魅惑の橋子       | 100000 |           1 |
-+---------+------------------+--------+-------------+
-2 rows in set (0.00 sec)
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-

【練習問題】 SQL/Question2/q2.txt

@@ -0,0 +1,29 @@
+問1
+CREATE TABLE item_category(category_id INT PRIMARY KEY AUTO_INCREMENT, category_name VARCHAR(256) NOT NULL);
+INSERT INTO item_category (category_name) VALUES(1,'家具');
+INSERT INTO item_category (category_name) VALUES('飲料');
+INSERT INTO item_category (category_name) VALUES('食品');
+
+問2
+CREATE TABLE item(item_id INT PRIMARY KEY AUTO_INCREMENT, name VARCHAR(256) NOT NULL, price INT NOT NULL,category_id INT, FOREIGN KEY(category_id) REFERENCES item_category(category_id));
+
+問3
+SELECT item.category_id, item.item_id, item.name, item.price,item_category.category_name FROM item INNER JOIN item_category ON item.category_id = item_category.category_id;
+
+問4
+SELECT item.category_id, item.item_id, item.name, item.price,item_category.category_name FROM item INNER JOIN item_category ON item.category_id = item_category.category_id ORDER BY price ASC;
+
+問5
+SELECT item.category_id, item.item_id, item.name, item.price,item_category.category_name FROM item INNER JOIN item_category ON item.category_id = item_category.category_id WHERE category_name ='家具';
+
+問6
+SELECT item.category_id, item.item_id, item.name, item.price,item_category.category_name FROM item INNER JOIN item_category ON item.category_id = item_category.category_id WHERE item.price >= 1000 AND item.price <= 50000;
+
+問7
+SELECT COUNT(*) AS data_count FROM item;
+
+問8
+SELECT item.category_id, item.item_id, item.name, item.price,item_category.category_name FROM item INNER JOIN item_category ON item.category_id = item_category.category_id WHERE item.price = 150000;
+
+問9
+SELECT item.category_id, item.item_id, item.name, item.price,item_category.category_name FROM item INNER JOIN item_category ON item.category_id = item_category.category_id WHERE item.name LIKE '%の%'