Compare commits
4 Commits
| Author | SHA1 | Date | |
|---|---|---|---|
| e2bbc5f2ce | |||
| 7194c7fc91 | |||
| 5f891cef78 | |||
| 6f0f8bf830 |
25
【練習問題】 SQL/Question1/Q1.txt
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25
【練習問題】 SQL/Question1/Q1.txt
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@@ -0,0 +1,25 @@
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問1
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CREATE TABLE book_table(book_id INT,book_name VARCHAR(50),author_name VARCHAR(50),price INT,sales_flag INT);
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問2
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INSERT INTO book_table VALUES(10001,'TwoPeace','三田英一郎',420,1);
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INSERT INTO book_table VALUES(10002,'名探偵金田二','青山ふみや',460,1);
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INSERT INTO book_table VALUES(20001,'坊ちゃま','冬目漱岩',460,1);
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INSERT INTO book_table VALUES(30001,'西方見聞録','不明',1000,1);
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INSERT INTO book_table VALUES(40010,'吾輩は犬である','冬目漱岩',420,1);
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問3
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SELECT book_name,author_name FROM book_table;
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問4
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UPDATE book_table SET author_name = 'マール=コ=ポロ' WHERE book_id = 30001;
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UPDATE book_table SET sales_flag = 0 WHERE book_id = 30001;
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問5
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SELECT * FROM book_table WHERE sales_flag = 1;
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問6
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SELECT * FROM book_table WHERE author_name = '冬目漱岩' AND price = 420;
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問7
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DELETE FROM book_table WHERE book_id = 20001;
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@@ -1,25 +0,0 @@
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問1
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CREATE TABLE book_table(book_id INT, book_name VARCHAR(50), author_name VARCHAR(50), price INT, sales_flag INT);
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問2
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INSERT INTO book_table VALUES (10001, 'TwoPeace', '三田英一郎', 420, 1);
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INSERT INTO book_table VALUES (10002, '名探偵金田二', '青山ふみや', 460, 1);
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INSERT INTO book_table VALUES (20001, '坊ちゃま', '冬目漱石', 460, 1);
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INSERT INTO book_table VALUES (30001, '西方見聞録', '不明', 1000, 1);
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INSERT INTO book_table VALUES (40010, '吾輩は犬である', '冬目漱石', 420, 1);
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問3
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SELECT book_name, author_name FROM book_table;
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問4
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UPDATE book_table SET author_name = 'マール=コ-=ポロ' WHERE book_id = 30001;
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UPDATE book_table SET sales_flag = 0 WHERE book_id = 30001;
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問5
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SELECT * FROM book_table WHERE sales_flag = 1;
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問6
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SELECT * FROM book_table WHERE author_name = '冬目漱石' AND price = 420;
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問7
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DELETE FROM book_table WHERE book_id = 20001;
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3
【練習問題】 SQL/Question2/Q2+α.txt
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3
【練習問題】 SQL/Question2/Q2+α.txt
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問1
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SELECT items.商品ID,items.商品名,items.価格,item_category.カテゴリ名 FROM items INNER JOIN item_category ON items.category_id = item_category.category_id ORDER BY 商品ID ASC;
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29
【練習問題】 SQL/Question2/Q2.txt
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29
【練習問題】 SQL/Question2/Q2.txt
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問1
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CREATE TABLE item_category(category_id INT AUTO_INCREMENT PRIMARY KEY,category_name VARCHAR(256) NOT NULL);
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INSERT INTO item_category(category_name)VALUES('家具')('飲料'),('食品');
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問2
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CREATE TABLE items(item_id INT PRIMARY KEY AUTO_INCREMENT,name VARCHAR(256) NOT NULL,price INT NOT NULL,category_id INT, FOREIGN KEY(category_id)REFERENCES item_category(category_id));
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INSERT INTO items(name,price,category_id) VALUE('ローマのテーブル',150000,1),('げーたるーど2000 500ml',370,2),('原始肉',2500,3),('魅惑の椅子',100000,1);
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問3
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SELECT item_category.category_id,items.item_id,items.name,items.price,item_category.category_name FROM items INNER JOIN item_category ON items.category_id = item_category.category_id;
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問4
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SELECT item_category.category_id,items.item_id,items.name,items.price,item_category.category_name FROM items INNER JOIN item_category ON items.category_id = item_category.category_id ORDER BY price ASC;
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問5
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SELECT item_category.category_id,items.item_id,items.name,items.price,item_category.category_name FROM items INNER JOIN item_category ON items.category_id = item_category.category_id WHERE category_name='家具';
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問6
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SELECT item_category.category_id,items.item_id,items.name,items.price,item_category.category_name FROM items INNER JOIN item_category ON items.category_id = item_category.category_id WHERE price BETWEEN 1000 AND 50000;
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問7
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SELECT COUNT(*) AS data_count FROM items;
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問8
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SELECT item_category.category_id,items.item_id,items.name,items.price,item_category.category_name FROM items INNER JOIN item_category ON items.category_id = item_category.category_id WHERE price = (SELECT MAX(price) FROM items);
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問9
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SELECT item_category.category_id,items.item_id,items.name,items.price,item_category.category_name FROM items INNER JOIN item_category ON items.category_id = item_category.category_id WHERE name LIKE '%の%';
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@@ -1,37 +0,0 @@
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問1
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CREATE TABLE item_category(category_id INT AUTO_INCREMENT, category_name VARCHAR(256) NOT NULL, PRIMARY KEY (category_id));
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INSERT INTO item_category (category_name) VALUES ('家具');
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INSERT INTO item_category (category_name) VALUES ('飲料');
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INSERT INTO item_category (category_name) VALUES ('食品');
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問2
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CREATE TABLE items(item_id INT AUTO_INCREMENT, name VARCHAR(256) NOT NULL, price INT NOT NULL, category_id INT, PRIMARY KEY (item_id));
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ALTER TABLE items ADD FOREIGN KEY(category_id) REFERENCES item_category(category_id);
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INSERT INTO items(name, price, category_id) VALUES('ローマのテーブル', 150000, 1);
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INSERT INTO items(name, price, category_id) VALUES('げーたるーど2000 500ml', 370, 2);
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INSERT INTO items(name, price, category_id) VALUES('原子肉', 2500, 3);
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INSERT INTO items(name, price, category_id) VALUES('魅惑の椅子', 100000, 1);
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問3
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SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id;
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問4
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SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id ORDER BY items.price ASC;
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問5
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SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE item_category.category_name = '家具';
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問6
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SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE price >= 1000 AND price <= 50000;
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問7
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SELECT COUNT(*) AS data_count FROM items;
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問8
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SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE price = (SELECT MAX(price) FROM items);
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問9
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SELECT item_category.category_id, items.item_id, items.name,items.price, item_category.category_name AS name FROM item_category INNER JOIN items ON item_category.category_id = items.category_id WHERE name LIKE '%の%';
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Reference in New Issue
Block a user